(\frac {x}{2019}+\frac {y}{2020}=2, \frac {2x}{2019}-\frac {... | Mathematics | SolveeIt | Solveeit

Today, August 19

Question

$\frac {x}{2019}+\frac {y}{2020}=2, \frac {2x}{2019}-\frac {y}{2020}=1$ , $∴(x, y)=$

A

(2019, 2020)

B

(2020, 2019)

C

(2019, 2019)

D

(2020, 2020)

Answer

(2019, 2020)

Explanation

Solution

The correct option is (A): (2019, 2020).