Question

$\frac{\text{2+3+5+…. to n terms}}{\text{2+5+8+….8 \,to \,8 \,\,terns}}$=9, then the value of n is

• A. 20
• B. 40
• C. 10
• D. 30

Answer 1

Answer: (D)

30

Answer 2

The correct option is (D): 30