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Question

Chemistry Question on Equilibrium

KpKc\frac{K_{p}}{K_{c}} for following reaction will be \quad\quad CO(g)+12O2(g)CO2(g)CO_{\left(g\right)}+\frac{1}{2}O_{2\left(g\right)}\rightarrow CO_{2\left(g\right)}

A

RTRT

B

1RT\frac{1}{RT}

C

1RT\frac{1}{\sqrt{RT}}

D

RT2\frac{RT}{2}

Answer

1RT\frac{1}{\sqrt{RT}}

Explanation

Solution

Δng=npnr=132\Delta_{n_g}=n_{p}-n_{r}=1-\frac{3}{2} Δng=12.\Delta _{n_g}=\frac{-1}{2}.HenceKp=Kc(RT)1/2 K_{p} = K_{c}\left(RT\right)^{-1/2} KpKc=1(RT)1/2=1RT\frac{K_{p}}{K_{c}}=\frac{1}{\left(RT\right)^{1/2}}=\frac{1}{\sqrt{RT}}