Question
Mathematics Question on Logarithmic Differentiation
dxd(xx) is equal to
A
xxlog(e/x)
B
xxlogex
C
logex
D
xxlogx
Answer
xxlogex
Explanation
Solution
Let y=xx
⇒logy=xlogx
On differentiating w.r.t. x, we get
y1dxdy=xx+logx
⇒dxdy=y(1+logx)
=xx(loge+logx)
=xx(logex)