Question
Mathematics Question on permutations and combinations
CoC1+2C1C2+3C2C3+....+nCn−1Cn =
A
2n(n−1)
B
2n(n+1)
C
2(n+1)(n+2)
D
Noneofthese
Answer
2n(n+1)
Explanation
Solution
C0C1+2C1C2+3C2C3+…+n−Cn−1Cn
=nC0nC1+2nC1nC2+3nC2nC3+…+nnCn−1nCn
=1n+2×n2n(n−1)+3×2n(n−1)3×2n(n−1)(n−2)+…+n×n1
=n+(n−1)+(n−2)+…+1
=∑n=2n(n+1)