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Question

Mathematics Question on Integration

∫1x[6(logx)2+7logx+2]dx=∫\frac{1}{x[6(logx)^2+7logx+2]}dx=

A

12log∣2logx+13logx+2∣+C\frac{1}{2}log|\frac{2logx+1}{3logx+2}|+C

B

log∣2logx+13logx+2∣+Clog|\frac{2logx+1}{3logx+2}|+C

C

log∣3logx+22logx+1∣+Clog|\frac{3logx+2}{2logx+1}|+C

D

12log∣3logx+22logx+1∣+C\frac{1}{2}log|\frac{3logx+2}{2logx+1}|+C

Answer

log∣2logx+13logx+2∣+Clog|\frac{2logx+1}{3logx+2}|+C

Explanation

Solution

The correct answer is Option (B) : log∣2logx+13logx+2∣+Clog|\frac{2logx+1}{3logx+2}|+C