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Question

Mathematics Question on Trigonometric Functions

1−tan⁡215∘1+tan⁡215∘=\frac{1 -\tan^2 15^\circ}{1 + \tan^2 15^\circ} =

A

11

B

3\sqrt{3}

C

32\frac{\sqrt{3}}{2}

D

22

Answer

32\frac{\sqrt{3}}{2}

Explanation

Solution

1−tan⁡215∘1+tan⁡215∘=cos⁡(2(15∘)) \frac{1 -\tan^2 15^\circ}{1 + \tan^2 15^\circ} = \cos(2(15^\circ))
=cos⁡30∘=32= \cos 30^\circ = \frac{\sqrt{3}}{2}