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Question

Mathematics Question on Algebra

12.5+15.8+18.11+...+1(3n−1)(3n+2)\frac{1}{2.5}+\frac{1}{5.8}+\frac{1}{8.11}+...+\frac{1}{(3n-1)(3n+2)} is equal to

A

n3n+2\frac{n}{3n+2}

B

n5n+4\frac{n}{5n+4}

C

n6n+2\frac{n}{6n+2}

D

n6n+4\frac{n}{6n+4}

Answer

n6n+4\frac{n}{6n+4}

Explanation

Solution

The correct option is (D): n6n+4\frac{n}{6n+4}