Question

Four resistances 10 Ω, 5 Ω, 7 Ω and 3 Ω are connected so that they form the sides of a rectangle AB, BC, CD and DA respectively. Another resistance of 10 Ω is connected across the diagonal AC. The equivalent resistance between A&B is

• A. 2 Ω
• B. 5 Ω
• C. 7 Ω
• D. 10 Ω

Answer 1

Answer: (B)

5 Ω

Answer 2

So $R_{eq} = \frac{10 \times 10}{10 + 10} = 5\Omega$