Solveeit Logo
Login

Question

Question: Four plates of equal area \(A\) are separated by equal distances ![](https://cdn.pureessence.tech/c...

Four plates of equal area AA are separated by equal distances and are arranged as shown in the figure. The equivalent capacity is

A

2ε0Ad\frac { 2 \varepsilon _ { 0 } A } { d }

B

3ε0Ad\frac { 3 \varepsilon _ { 0 } A } { d }

C

3ε0Ad\frac { 3 \varepsilon _ { 0 } A } { d }

D

ε0Ad\frac { \varepsilon _ { 0 } A } { d }

Answer

2ε0Ad\frac { 2 \varepsilon _ { 0 } A } { d }

Explanation

Solution

The given circuit is equivalent to a parallel combination two identical capacitors. Hence equivalent capacitance between A and B is

C = ε0Ad+ε0Ad\frac { \varepsilon _ { 0 } A } { d } + \frac { \varepsilon _ { 0 } A } { d } =2ε0Ad= \frac { 2 \varepsilon _ { 0 } A } { d }