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Question

Physics Question on rotational motion

Four particles each of mass 1 kg are placed at four corners of a square of side 2 m. Moment of inertia of system about an axis perpendicular to its plane and passing through one of its vertices is _____ kgm2.
Problem figure

Answer

Consider a square of side 2 m. For each mass located at distances:

I=ma2+ma2+m(2a)2+m(2a)2I = ma^2 + ma^2 + m(2a)^2 + m(2a)^2

=1×22+1×22+1×4+1×4=4+4+4+4+8=16kg m2= 1 \times 2^2 + 1 \times 2^2 + 1 \times 4 + 1 \times 4 = 4 + 4 + 4 + 4 + 8 = 16 \, \text{kg m}^2