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Question

Physics Question on kinetic theory

Four molecules of a gas have speeds 1,2,31,2,3 and 4kms14\, kms ^{-1}. The value of rms speed of the gas molecules is :

A

1215kms1\frac{1}{2} \sqrt{15} kms ^{-1}

B

1210kms1\frac{1}{2} \sqrt{10} kms ^{-1}

C

2.5kms12.5 \,kms^{-1}

D

152kms1\frac{15}{2} kms ^{-1}

Answer

152kms1\frac{15}{2} kms ^{-1}

Explanation

Solution

The square root of vˉ2\bar{v}^{2} is called the root mean square velocity (rms) speed of the molecules.
vrms=vˉ2v_{ rms } =\sqrt{\bar{v}^{2}}
=v12+v22+v32+v424=\sqrt{\frac{v_{1}^{2}+v_{2}^{2}+v_{3}^{2}+v_{4}^{2}}{4}}
=(1)2+(2)2+(3)2+(4)24=\sqrt{\frac{(1)^{2}+(2)^{2}+(3)^{2}+(4)^{2}}{4}}
=1+4+9+164=\sqrt{\frac{1+4+9+16}{4}}
=304=\sqrt{\frac{30}{4}}
=152kms1=\sqrt{\frac{15}{2}} kms ^{-1}