Solveeit Logo

Question

Question: Four massless springs whose force constants are 2k, 2k, k and 2k respectively are attached to a mass...

Four massless springs whose force constants are 2k, 2k, k and 2k respectively are attached to a mass M kept on a frictionless plane as shown in the figure. If the mass M is displaced in the horizontal direction, then the frequency of the system is:

A) 12πk4M\dfrac{1}{{2\pi }}\sqrt {\dfrac{k}{{4M}}}
B) 12π4kM\dfrac{1}{{2\pi }}\sqrt {\dfrac{{4k}}{M}}
C) 12πk7M\dfrac{1}{{2\pi }}\sqrt {\dfrac{k}{{7M}}}
D) 12π7k7M\dfrac{1}{{2\pi }}\sqrt {\dfrac{{7k}}{{7M}}}

Explanation

Solution

Formula for frequency is:
12π1LC\dfrac{1}{{2\pi }}\sqrt {\dfrac{1}{{LC}}} (L is the inductor, C is the capacitor)
As per electrical and mechanical analogy conversion, in force current analogy M is the capacitor (C) and k is the reciprocal of the inductor (1/L).
Let’s find the value of k using series and parallel connections (using 1/L = k, in series connections are added with their direct connections and the parallel connection have reciprocal addition).

Complete step by step solution:
As we are provided with an inductor and capacitor in the system then we will add the reciprocal of the inductor for the series connection.
K=K1+K2K = {K_1} + {K_2}
First, we will do the calculation for series connection:
K1=12k+12k K1=2k×2k2k+2k \Rightarrow {K_1} = \dfrac{1}{{2k}} + \dfrac{1}{{2k}} \\\ \Rightarrow {K_1} = \dfrac{{2k \times 2k}}{{2k + 2k}} (Taking LCM)
K1=2k2k=1k\Rightarrow {K_1} = \dfrac{{2k}}{{2k}} = 1k
Now, we will calculate for the springs in parallel:
K2=112k+11k K2=2k+k=3k \Rightarrow {K_2} = \dfrac{1}{{\dfrac{1}{{2k}}}} + \dfrac{1}{{\dfrac{1}{k}}} \\\ \Rightarrow {K_2} = 2k + k = 3k (in parallel connection we have to take the reciprocal of the spring constants)
Total value of K comes out to be:
K=K1+K2 K=k+3k=4k \Rightarrow K = {K_1} + {K_2} \\\ \Rightarrow K = k + 3k = 4k
From the equation of frequency:
f=12π1M1K f=12πKM \Rightarrow f = \dfrac{1}{{2\pi }}\sqrt {\dfrac{1}{{M\dfrac{1}{K}}}} \\\ \Rightarrow f = \dfrac{1}{{2\pi }}\sqrt {\dfrac{K}{M}} (We have substituted the value of LC as per formula of frequency)
f=12π4kM\Rightarrow f = \dfrac{1}{{2\pi }}\sqrt {\dfrac{{4k}}{M}} (We have substituted the values M and K).

Hence, Option B is correct.

Note: In the question above we have used electrical to mechanical equivalent system of force current, where current is acting as the force in a mechanical system, mass as capacitor, frictional coefficient as reciprocal of R resistor, spring constant as reciprocal of L inductor, displacement as magnetic flux and velocity as voltage.