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Question

Physics Question on Oscillations

Four massless springs whose force constants are 2k,2k,k2k, 2k, k and 2k2k respectively are attached to a mass MM kept on a frictionless plane as shown in the figure. If the mass MM is displaced in the horizontal direction, then the frequency of the system is

A

12πk4M\frac{1}{2\pi} \sqrt{\frac{k}{4M}}

B

12π4kM\frac{1}{2\pi} \sqrt{\frac{4k}{M}}

C

12πk7M\frac{1}{2\pi} \sqrt{\frac{k}{7M}}

D

12π7kM\frac{1}{2\pi} \sqrt{\frac{7k}{M}}

Answer

12π4kM\frac{1}{2\pi} \sqrt{\frac{4k}{M}}

Explanation

Solution

Two springs on the L.H.S. of mass M are in series and two springs on the R.H.S. of mass M are in parallel. These combinations of springs will be considered in parallel to mass M. Thus effective spring constant, K=2k×2k2κ+2k+(k+2k)=4k\quad\quad K=\frac{2k\times2k}{2\kappa+2k}+\left(k+2k\right)=4k Frequency?=12πKM=12π4kM\therefore\quad Frequency ? = \frac{1}{2\pi}\sqrt{\frac{K}{M}}=\frac{1}{2\pi}\sqrt{\frac{4k}{M}}