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Question

Physics Question on System of Particles & Rotational Motion

Four identical thin rods each of mass M and length ll, form a square frame. Moment of inertia of this frame about an axis through the centre of the square and perpendicular to its plane is

A

23Ml2\frac{2}{3}Ml^2

B

133Ml2\frac{13}{3}Ml^2

C

13Ml2\frac{1}{3}Ml^2

D

43Ml2\frac{4}{3}Ml^2

Answer

43Ml2\frac{4}{3}Ml^2

Explanation

Solution

I=4×[M212+M(2)2]I =4 \times\left[\frac{ M \ell^{2}}{12}+ M \left(\frac{\ell}{2}\right)^{2}\right]
the parallel axis theorem =43M2=\frac{4}{3} M \ell^{2}