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Question: Four identical charges \(+ 50\mu C\) each are placed, one at each corner of a square of side\(2m\). ...

Four identical charges +50μC+ 50\mu C each are placed, one at each corner of a square of side2m2m. How much external energy is required to bring another charge of +50μC+ 50\mu C from infinity to the centre of the square

(Given14πε0=9×109Nm2C2)\left( \text{Given}\frac{1}{4\pi\varepsilon_{0}} = 9 \times 10^{9}\frac{Nm^{2}}{C^{2}} \right)

A

64J64J

B

41J41J

C

16J16J

D

10J10J

Answer

64J64J

Explanation

Solution

Potential at the centre of square

V=4×(9×109×50×1062/2)=902×104VV = 4 \times \left( \frac{9 \times 10^{9} \times 50 \times 10^{- 6}}{2/\sqrt{2}} \right) = 90\sqrt{2} \times 10^{4}V

Work done in bringing a charge (q = 50 μC) from ∞ to centre (O) of the square is

W=q(V0V)=qV0W = q(V_{0} - V_{\infty}) = qV_{0}

W=50×106×902×104=64JW = 50 \times 10^{- 6} \times 90\sqrt{2} \times 10^{4} = 64J