Question

Four identical capacitors are connected in series with a 10V battery as shown in the figure. The point N is earthed. The potentials of points A and B are

• A.
• B. $7.5 V - 2.5 V$
• C. $5 V - 5 V$
• D. $7.5 \mathrm {~V} , 2.5 \mathrm {~V}$

Answer 1

Answer: (B)

$7.5 V - 2.5 V$

Answer 2

Potential difference across each capacitor will be $\frac { 10 } { 4 } = 2.5 \mathrm {~V}$

Hence potential difference between A & N i.e., $V _ { A } - V _ { N } = 2.5 + 2.5 + 2.5 = 7.5 \mathrm {~V}$

⇒ $V _ { A } - 0 = V _ { A } = 7.5 \mathrm {~V}$ While $V _ { N } - V _ { B } = 2.5$

⇒ $0 - V _ { B } = 2.5$ ⇒ $V _ { B } = - 2.5 \mathrm {~V}$