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Question: Four equal charges, each +q are placed on the four corners of a square of side a. Then the coulomb f...

Four equal charges, each +q are placed on the four corners of a square of side a. Then the coulomb force experienced by one charge due to the rest of three is - (K=14πε0)\left( K = \frac{1}{4\pi\varepsilon_{0}} \right)

A

(22+1)Kq2/2a2(2\sqrt{2} + 1)Kq^{2}/2a^{2}

B

3Kq2/a2

C

22\sqrt{2}Kq2/a2

D

Zero

Answer

(22+1)Kq2/2a2(2\sqrt{2} + 1)Kq^{2}/2a^{2}

Explanation

Solution

F12 = F14 = kq2a2\frac { \mathrm { kq } ^ { 2 } } { \mathrm { a } ^ { 2 } }

Resultant of F12 & F14

= F122+F142\sqrt { \mathrm { F } _ { 12 } ^ { 2 } + \mathrm { F } _ { 14 } ^ { 2 } }

= F122+F122\sqrt { \mathrm { F } _ { 12 } ^ { 2 } + \mathrm { F } _ { 12 } ^ { 2 } }

= F122\mathrm { F } _ { 12 } \sqrt { 2 }

\ Net force on

charge q is

F = F122\mathrm { F } _ { 12 } \sqrt { 2 } + F13

= kq2a22\frac { \mathrm { kq } ^ { 2 } } { \mathrm { a } ^ { 2 } } \sqrt { 2 } +.