Question

Four children A, B, C and D are having some chocolates each.
A gives B as many as he already has, he gives C twice of what C already has and he gives D thrice of what D already has.
Now, D gives ($\frac 18$)th of his own chocolates to B.
Then A gives 10% chocolates he now owns to C and 20% to B.
Finally, all of them have 35 chocolates each. What is the original number of chocolates each had in the beginning?

• A. A-110, B-10, C-10, D-10
• B. A-90, B-20, C-20, D-10
• C. A-70, B-25, C-25, D-20
• D. A-125, B-5, C-5, D-5

Answer 1

Answer: (A)

A-110, B-10, C-10, D-10

Answer 2

The correct option is (A): A-110, B-10, C-10, D-10.