Question

Four capacitors of each of capacity $3\mu F$are connected as shown in the adjoining figure. The ratio of equivalent capacitance between $A$ and $B$ and between $A$ and $C$ will be

• A. 4 : 3
• B. 3 : 4
• C. 2 : 3
• D. 3 : 2

Answer 1

Answer: (A)

4 : 3

Answer 2

$C_{AB} = 3 + \frac{3}{3} = 4,\mu F$ $C_{AC} = \frac{3}{2} + \frac{3}{2} = 3\mu F$

∴$C_{AB}:C_{AC} = 4: ⥂ 3$