Solveeit Logo
Login

Question

Question: Formation of phosphoenolpyruvate from 2-pliosphoglycerate is A. Dehydration B. Dehydrogenation ...

Formation of phosphoenolpyruvate from 2-pliosphoglycerate is
A. Dehydration
B. Dehydrogenation
C. Oxidation
D. Hydration

Explanation

Solution

Glycolysis is a metabolic pathway that involves catabolism (breakdown) of six glucose molecules into two molecules of Pyruvate. It is a 1010 step pathway. It is a biological process that takes place in the cytosol. It is an aerobic pathway and involves the lysis of glucose for energy production.

Complete answer:
We know that Glycolysis is a process where the breakdown of six glucose molecules occurs in order to form two molecules of pyruvate. It is a ten step pathway and occurs in the cytosol.
The first five steps involve the Preparatory phase/energy investment phase as in these steps the energy is invested. The ATP is utilized in these steps.

The first five steps include the following conversions-
- Glucose→Glucose−6−phosphate  (ATP→ADP)\text{Glucose} \to \text{Glucose} - 6 - \text{phosphate}\;(ATP \to ADP)
- Glucose−6−phosphate→Fructose−6−phosphate\text{Glucose} - 6 - \text{phosphate} \to \text{Fructose} - 6 - \text{phosphate}
- Fructose−6−phosphate→Fructose−1,6−bisphosphate  (ATP→ADP)\text{Fructose} - 6 - \text{phosphate} \to \text{Fructose} - 1,6 - \text{bisphosphate}\;(ATP \to ADP)
- Fructose−1,6−bisphosphate→Glyceraldehyde−3−phosphate +Dihydroxyacetone phosphate\text{Fructose} - 1,6 - \text{bisphosphate} \to \text{Glyceraldehyde} - 3 - \text{phosphate }+ \text{Dihydroxyacetone phosphate}

The next five steps include the Pay off phase/Energy generation phase and include the following conversions-
- Dihydroxyacetone phosphate→Glyceraldehyde−3−phosphate\text{Dihydroxyacetone phosphate} \to \text{Glyceraldehyde} - 3 - \text{phosphate}
- Glyceraldehyde−3−phosphate→1,3−bisphosphoglycerate  (NAD+→NADH)\text{Glyceraldehyde} - 3 - \text{phosphate} \to 1,3 - \text{bisphosphoglycerate}\;(NA{D^ + } \to NADH)
- 1,3−bisphosphoglycerate→3−phosphoglycerate  (ADP→ATP)1,3 - \text{bisphosphoglycerate} \to 3 - \text{phosphoglycerate}\;(ADP \to ATP)
- 3−phosphoglycerate→2−phosphoglycerate3 - \text{phosphoglycerate} \to 2 - \text{phosphoglycerate}
- 2−phosphoglycerate→Phosphoenolpyruvate,  2  H2O↑2 - \text{phosphoglycerate} \to \text{Phosphoenolpyruvate},\;2\;{H_2}O \uparrow
- phosphoenol pyruvate→Pyruvate  (2ADP→2ATP)\text{phosphoenol pyruvate} \to \text{Pyruvate} \;(2ADP \to 2ATP)

The above steps clearly indicate the formation of Pyruvate from Glucose. So, we can say that the formation of phosphoenolpyruvate from 2-pliosphoglycerate involves dehydration as there is the removal of 22 molecules of water.

Hence, the correct answer is option (A).

Additional information:
• Dehydration- It involves the loss of water.
• Dehydrogenation- It involves the removal of hydrogen and not of the whole water molecule.
• Oxidation- It involves the loss of electrons.
• Hydration- It involves the addition of water.

Note: Glycolysis is an aerobic pathway. The major steps include-
Glucose always produces two molecules of pyruvic acids.
Initially ATP is required and then ATP is produced.
So, a total of six ATP are produced during aerobic reaction.