Formation of (\ce{PCl\_3}) is explained on the basis of what... | Chemistry | SolveeIt

Formation of $\ce{PCl_3}$ is explained on the basis of what hybridisation of phosphorus atom

$\ce{SP^2}$

$\ce{SP^3}$

$\ce{SP^3 d }$

$\ce{SP^3 d^2}$

Answer

$\ce{SP^3}$

Explanation

The type of hybridisation in an atom can be determined By using the formula

$H=\frac{1}{2}[V+Y-C+A]$

Here, $V=$ valence shell electrons of the central atom

$Y=$ number of monovalent atom

$C=$ total positive charge and

$A=$ total negative charge In case of $PCl _{3}$
$H=\frac{1}{2}[5+3]=4$

Hybridisation of phosphorus atom is $s p^{3}$ .

Pyramidal shape (due to presence of one lone pair of electron.)

Chemistry Question on Chemical bonding and molecular structure