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Question: Formation of ammonia is shown by the reaction, \[N_{2(g) + 3H_{2(g)}} \rightarrow 2NH_{3(g),}\Delta...

Formation of ammonia is shown by the reaction,

N2(g)+3H2(g)→2NH3(g),ΔrHo=−91.8kJmol−1N_{2(g) + 3H_{2(g)}} \rightarrow 2NH_{3(g),}\Delta_{r}H^{o} = - 91.8kJmol^{- 1}

What will be the enthalpy ofreaction for the decomposition of NH3NH_{3} according to the reaction?

2NH3(g)→N2(g)+3H2(g);ΔrHo=2NH_{3(g)} \rightarrow N_{2(g)} + 3H_{2(g)};\Delta_{r}H^{o} =?

A

−91.8kJmol−1- 91.8kJmol^{- 1}

B

+91.8kJmol−1+ 91.8kJmol^{- 1}

C

−45.9kJmol−1- 45.9kJmol^{- 1}

D

+45.9kJmol−1+ 45.9kJmol^{- 1}

Answer

+91.8kJmol−1+ 91.8kJmol^{- 1}

Explanation

Solution

: The sign,ΔH\Delta H,is reversed.