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Question

Chemistry Question on Thermodynamics

Formation of a solution from two components can be considered as : (i) Pure solvent \rightarrow separated solvent molecules, ΔH1\Delta H _{1} (ii) Pure solvent \rightarrow separated solvent molecules, ΔH2\Delta H _{2} (iii) Separated solvent and solute molecules \rightarrow solution, ΔH3\Delta H _{3} Solution so formed will be ideal if

A

ΔHSoln=ΔH1+ΔH2+ΔH3\Delta H_{\text{Soln}} = \Delta H_1 + \Delta H_2 + \Delta H_3

B

ΔHSoln=ΔH1+ΔH2ΔH3\Delta H_{\text{Soln}} = \Delta H_1 + \Delta H_2 - \Delta H_3

C

ΔHSoln=ΔH1ΔH2ΔH3\Delta H_{\text{Soln}} = \Delta H_1 - \Delta H_2 - \Delta H_3

D

ΔHSoln=ΔH3ΔH1ΔH2\Delta H_{\text{Soln}} = \Delta H_3 - \Delta H_1 - \Delta H_2

Answer

ΔHSoln=ΔH1+ΔH2+ΔH3\Delta H_{\text{Soln}} = \Delta H_1 + \Delta H_2 + \Delta H_3

Explanation

Solution

For ideal solution, ΔHsolution=ΔH1+ΔH2+ΔH3\Delta {{H}_{solution}}=\Delta {{H}_{1}}+\Delta {{H}_{2}}+\Delta {{H}_{3}}