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Question: Formation of \(240.8\)from \(K_{c}\)and \(K_{c}\)is an exothermic process. The equilibrium system ca...

Formation of 240.8240.8from KcK_{c}and KcK_{c}is an exothermic process. The equilibrium system can be represented as

Kp=167K_{p} = 167 1.896molL11.896molL^{- 1}

Which of the following will increase quantity of 4.38×104molL14.38 \times 10^{- 4}molL^{- 1}is the equilibrium mixture?

A

Increase in temperature, decrease in pressure, addition of 6.626molL16.626molL^{- 1}

B

Decrease in temperature and pressure, addition of 3.0×1010bar13.0 \times 10^{10}bar^{- 1}

C

Increase in temperature and pressure, removal of KpK_{p}

D

Decrease in temperature, increase in pressure, addition of KcK_{c}

Answer

Decrease in temperature, increase in pressure, addition of KcK_{c}

Explanation

Solution

: Exothermic reaction, decrease in number of moles, increase in concentration of reactants.