Question
Question: Formalin is used in the preparation of: (a)- Bakelite (b)- Nylon (c)- Styrene (d)- Teflon...
Formalin is used in the preparation of:
(a)- Bakelite
(b)- Nylon
(c)- Styrene
(d)- Teflon
Solution
Some of the compounds given in the options are polymers made up of monomers. Bakelite is a polymer formed from phenol and formaldehyde. Nylon is a polymer that has many forms and it is made up of many types of monomers like cyclohexane, Hexamethylenediamine, Sebacic acid, and Adipic acid. Styrene itself is a monomer that is used to prepare polystyrene. Teflon is a polymer that is formed from tetrafluoroethane.
Complete answer:
Polymers are those compounds having very high molecular mass and a large number of molecules that are made up of monomers.
Formalin is a solution in which 40% of formaldehyde is present, so 40% formaldehyde is known as Formalin.
Now let us discuss all the compounds given in the options:
Bakelite is a polymer formed from phenol and formaldehyde. Phenol and formaldehyde combine to form novalac molecules, which combine in n numbers to form Bakelite.
Nylon is a polymer that has many forms and it is made up of many types of monomers like cyclohexane, Hexamethylenediamine, Sebacic acid, and Adipic acid.
Styrene itself is a monomer that is used to prepare polystyrene.
Teflon is a polymer that is formed from tetrafluoroethane.
So, from the above options, Bakelite is formed from formaldehyde, therefore, we can say that formalin is used in the formation of Bakelite. The formation of Bakelite is given below:
Therefore, the correct answer is an option (a)- Bakelite.
Note:
Polymers are formed by two processes, i.e., addition polymerization and condensation polymerization, and Bakelite is an example of condensation polymerization because there is a loss of water molecules.