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Question: Forces proportional to \[{\text{AB}}\], \[{\text{BC}}\] and \[{\text{2CA}}\] act along the sides of ...

Forces proportional to AB{\text{AB}}, BC{\text{BC}} and 2CA{\text{2CA}} act along the sides of triangle ABC{\text{ABC}} in order. Their resultant represented in magnitude and direction as
A. CA\overrightarrow {{\text{CA}}}
B. AC\overrightarrow {{\text{AC}}}
C. BC\overrightarrow {{\text{BC}}}
D. CB\overrightarrow {{\text{CB}}}

Explanation

Solution

We are asked to find the resultant of three vectors AB\overrightarrow {{\text{AB}}} , BC\overrightarrow {{\text{BC}}} and 2CA{\text{2}}\overrightarrow {{\text{CA}}} along three sides of the triangle ABC. First, find the resultant of vectors AB\overrightarrow {{\text{AB}}} and BC\overrightarrow {{\text{BC}}} , for this you will need to use triangle law of vectors. Using this law find the resultant of vectors AB\overrightarrow {{\text{AB}}} and BC\overrightarrow {{\text{BC}}} and then we with vector obtained find its resultant with vector 2CA{\text{2}}\overrightarrow {{\text{CA}}} .

Complete step by step answer:
Given, the forces proportional to AB{\text{AB}}, BC{\text{BC}} and 2CA{\text{2CA}} act along the sides of triangle ABC{\text{ABC}} in order.Let the force acting along the side AB{\text{AB}} be AB\overrightarrow {{\text{AB}}} , the force acting along the side BC{\text{BC}} be BC\overrightarrow {{\text{BC}}} and the force acting along the side AC{\text{AC}} be AC\overrightarrow {{\text{AC}}} .The force 2CA{\text{2}}\overrightarrow {{\text{CA}}} will act opposite to force AC\overrightarrow {{\text{AC}}} .

Let us draw a diagram for the problem.

To find the resultant vector of AB\overrightarrow {{\text{AB}}} and BC\overrightarrow {{\text{BC}}} , we will use the triangle law of vectors, according to which if two vectors represents two sides of a triangle with their magnitude and direction then the resultant of the two vectors is represented by the third side of the triangle.Here, AB\overrightarrow {{\text{AB}}} and BC\overrightarrow {{\text{BC}}} are two vectors along two sides of triangle ABC so the resultant vector will be along the side AC{\text{AC}} that will be AC\overrightarrow {{\text{AC}}} .

Now, the resultant of vector 2CA{\text{2}}\overrightarrow {{\text{CA}}} and AC\overrightarrow {{\text{AC}}} will be,
R=2CA+AC\overrightarrow {\text{R}} = {\text{2}}\overrightarrow {{\text{CA}}} + \overrightarrow {{\text{AC}}}
The vector AC\overrightarrow {{\text{AC}}} can be written as (CA)\left( { - \overrightarrow {{\text{CA}}} } \right). Substituting this value in the above equation we get,
R=2CACA\overrightarrow {\text{R}} = {\text{2}}\overrightarrow {{\text{CA}}} - \overrightarrow {{\text{CA}}}
R=CA\therefore \overrightarrow {\text{R}} = \overrightarrow {{\text{CA}}}
Therefore, the resultant vector is CA\overrightarrow {{\text{CA}}} with magnitude CA{\text{CA}} and direction from point C to point A.

Hence, the correct answer is option A.

Note: A vector is a quantity which has both magnitude and direction. There are two important laws of vector addition which are triangle law and parallelogram of vector addition. In the above question we have discussed triangle law of vector addition.Parallelogram law of vector addition states that if two vectors represent two adjacent sides of a parallelogram then the diagonal from the common point of the two adjacent sides represents the resultant or sum of the two vectors.