Solveeit Logo

Question

Physics Question on laws of motion

Force required to move a mass of 1kg1 \,kg at rest on a horizontal rough plane ( μ=0.1\mu =0.1 and g=9.8ms2g=9.8\,m{{s}^{2}} ) is

A

0.980.98 N

B

0.490.49 N

C

9.89.8 N

D

4.94.9 N

Answer

0.980.98 N

Explanation

Solution

Given that μ=0.1\mu=0.1 and g=9.8m/s2g=9.8\, m / s ^{2}
So, F=fr=μN=μmgF =f_{r}=\mu N=\mu mg
=0.1×1×9.8=0.98N=0.1 \times 1 \times 9.8=0.98\, N