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Question: Force of attraction between two point charges \(Q\) and – Q separated by \(dmetre\) is\(F_{e}\). Whe...

Force of attraction between two point charges QQ and – Q separated by dmetredmetre isFeF_{e}. When these charges are placed on two identical spheres of radius R=0.3dR = 0.3d whose centres are dmetredmetreapart, the force of attraction between them is

A

Greater than FeF_{e}

B

Equal to FeF_{e}

C

Less than FeF_{e}

D

Less than FeF_{e}

Answer

Greater than FeF_{e}

Explanation

Solution

Separation between the spheres is not too large as compared to their radius so due to induction effect redistribution of charge takes place. Hence effective charge separation decreases so force increases.