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Question: Force between two unit pole strength placed at a distance of one metre is...

Force between two unit pole strength placed at a distance of one metre is

A

1 N

B

C

D

4π×10−7N4 \pi \times 10 ^ { - 7 } N

Answer

Explanation

Solution

F=10−7×m2r2=10−7(1)2(1)2=10−7 NF = 10 ^ { - 7 } \times \frac { m ^ { 2 } } { r ^ { 2 } } = \frac { 10 ^ { - 7 } ( 1 ) ^ { 2 } } { ( 1 ) ^ { 2 } } = 10 ^ { - 7 } \mathrm {~N}