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Question: Force between two identical bar magnets whose centres are r metre apart is 4.8 N, when their axes ar...

Force between two identical bar magnets whose centres are r metre apart is 4.8 N, when their axes are in the same line. If separation is increased to 2r, the force between them is reduced to

A

2.4N

B

1.2N

C

0.6N

D

0.3N

Answer

0.3N

Explanation

Solution

In magnetic dipole, force ∝1r4\propto \frac { 1 } { r ^ { 4 } }

Hence new force =4.824=4.816=0.3 N= \frac { 4.8 } { 2 ^ { 4 } } = \frac { 4.8 } { 16 } = 0.3 \mathrm {~N}