Question

Force acting on a particle is given by F = $\frac{A–x}{Bt}$, where x is in metre and t is in seconds. The dimensions of B is –

• A. $\text{MLT}\text{ }^{\text{-2}}$
• B. $M^{\text{-1}}T^{\text{- 3}}$
• C. $M^{\text{-1}}T$
• D. $\text{MT}\text{ }^{\text{-1}}$

Answer 1

Answer: (C)

$M^{\text{-1}}T$

Answer 2

[F] = $\frac{\lbrack A–x\rbrack}{\lbrack B\rbrack\lbrack t\rbrack}$

[B] = $\frac{\lbrack L\rbrack}{\lbrack MLT^{–2}\rbrack\lbrack T\rbrack}$ $= \ \lbrack M^{\text{-1}}T^{1}\rbrack$