Question
Question: For \(xA + yB\) \(\to \) \(zC\), \[-\dfrac{d[A]}{dt}=-\dfrac{d[B]}{dt}=1.5\dfrac{d[C]}{dt}\] t...
For xA+yB → zC,
−dtd[A]=−dtd[B]=1.5dtd[C]
then x, y and z are.
A. 1, 1, 1
B. 3, 2, 3
C. 3, 3, 2
D. 2, 2, 3
Solution
We should know how to write the change in concentration of the reactants versus change in concentration of the product in a chemical reaction.
For xA+yB → zC chemical reaction, the change in concentration of the reactants versus change in concentration of the product is as follows.
−x1dtd[A]=−y1dtd[B]=z1dtd[C]
Complete step by step solution:
- In the question it is asked to find the x, y and z values for the given chemical reaction.
- For xA + yB → zC chemical reaction, the change in concentration of the reactants versus change in the concentration of the products is as follows.
−x1dtd[A]=−y1dtd[B]=z1dtd[C]→(1)
- The given relationship between the reactants and the products in the question is as follows.
−dtd[A]=−dtd[B]=1.5dtd[C]
- We can simplify the above relationship to get the values of the x, y and z.
−dtd[A]=−dtd[B]=1.5dtd[C]
- Initially multiply the above equation with 31