Question

for which value of $\lambda$ is the function ,$f(x) = \begin{cases} \lambda(x^2-2x) & \text{if } x \leq 0 \\\ 4x+1& \text{if } x > 0 \end{cases}$ continuous at $x=0 ?$

• A. $\lambda=0$
• B. $\lambda=1$
• C. $\lambda=-1$
• D. for no value of $\lambda$

Answer 1

Answer: (D)

for no value of $\lambda$

Answer 2

The correct option is (D):for no value of $\lambda$