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Question: For which among the following equimolar aqueous solutions Van't Hoff factor has the lowest value? ...

For which among the following equimolar aqueous solutions Van't Hoff factor has the lowest value?
a.) Aluminium Chloride
b.) Potassium Sulphate
c.) Ammonium Chloride
d.) Urea

Explanation

Solution

Hint: The Van’t Hoff factor is a measure of the effect of a solute on colligative properties, such as osmotic pressure, relative lowering in vapour pressure, boiling point elevation and freezing point depression. We need to find the Van’t Hoff factor of each of the mentioned options, to determine the one having the lowest.

Complete step-by-step answer:
In the first place, we have Aluminium Chloride. The chemical formula of Aluminium Chloride is AlCl3\text{AlC}{{\text{l}}_{\text{3}}}. We know Van’t Hoff factor is defined as i.
So in the case of AlCl3\text{AlC}{{\text{l}}_{\text{3}}}, the value of i is 4.
The equation is given below:
AlCl3  Al3+ + 3Cl\text{AlC}{{\text{l}}_{\text{3}}}\text{ }\xrightarrow{{}}\text{ A}{{\text{l}}^{\text{3+}}}\text{ + 3C}{{\text{l}}^{-}}
Next we have Potassium Sulphate. The chemical formula of Potassium Sulphate is K2SO4{{\text{K}}_{\text{2}}}\text{S}{{\text{O}}_{\text{4}}}.
So in case of K2SO4{{\text{K}}_{\text{2}}}\text{S}{{\text{O}}_{\text{4}}}, the value of i is 3.
The equation is given below:
K2SO4  2K+ + SO42{{\text{K}}_{\text{2}}}\text{S}{{\text{O}}_{\text{4}}}\text{ }\xrightarrow{{}}\text{ 2}{{\text{K}}^{\text{+}}}\text{ + S}{{\text{O}}_{\text{4}}}^{\text{2}-}
Now, for Ammonium Chloride, we have the formula as NH4Cl\text{N}{{\text{H}}_{\text{4}}}\text{Cl}.
So in the case of NH4Cl\text{N}{{\text{H}}_{\text{4}}}\text{Cl}, the value of i is 2.
The equation is given below:
NH4Cl  NH4+ + Cl\text{N}{{\text{H}}_{\text{4}}}\text{Cl }\xrightarrow{{}}\text{ N}{{\text{H}}_{\text{4}}}^{\text{+}}\text{ + C}{{\text{l}}^{-}}
Lastly, we have Urea. We know that the aqueous solution of Urea Van't Hoff factor has the lowest value. Urea is non electrolyte and does not dissociate an aqueous solution. Hence the value of i is 1.

So we can see that Urea has the lowest Van’t Hoff value. So the correct answer is Option D.

Note: To measure the Van't Hoff factor we need to find the ratio between the actual concentration of particles produced when the substance is dissolved and the concentration of a substance as calculated from its mass.
For most non electrolytes dissolved in water the Van't Hoff factor is essentially 1. For most ionic compounds dissolved in water, the Van't Hoff factor is equal to the number of discrete ions in a formula unit of the substance. This is true for ideal solutions only, as occasionally ion pairing occurs in solution.