Question

For what values of $x$, the numbers $-1,\,x,-3/4$ are in $GP$ ?

• A. $3/2$
• B. $\sqrt{3}/4$
• C. $\sqrt{3}/2$
• D. $3/\sqrt{2}$

Answer 1

Answer: (C)

$\sqrt{3}/2$

Answer 2

Given, $-1,x,\frac{-3}{4}$ are in GP $\therefore$ ${{x}^{2}}=(-1)\left( \frac{-3}{4} \right)$ $\Rightarrow$ $x=\sqrt{\frac{3}{4}}$ $\Rightarrow$ $x=\frac{\sqrt{3}}{2}$