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Question: For what values of the parameter ‘a’ are there real values of x such that 5<sup>1 + x</sup> + 5<sup>...

For what values of the parameter ‘a’ are there real values of x such that 51 + x + 51 – x, a2\frac{a}{2}, 25x + 25–x are three consecutive terms of an A.P. –

A

a < 12

B

a < –12

C

a ³ 12

D

None of these

Answer

a ³ 12

Explanation

Solution

2(a2)\left( \frac{a}{2} \right) = (51 + x + 51 – x) + (25x + 25–x)

̃ a = 5 (5x + 5–x) + (52x + 5–2x)

= 5 {(5x/2 – 5–x/2)2 + 2.5x/2 . 5–x/2} + {(5x – 5–x)2 + 2 . 5x . 5–x}

= 5 {(5x/2 – 5–x/2)2 + 2} + (5x – 5–x)2 + 2 a ³ 5 × 2 + 2 a ³ 12.