Question
Question: For what values of the parameter ‘a’ are there real values of x such that 5<sup>1 + x</sup> + 5<sup>...
For what values of the parameter ‘a’ are there real values of x such that 51 + x + 51 – x, 2a, 25x + 25–x are three consecutive terms of an A.P. –
A
a < 12
B
a < –12
C
a ³ 12
D
None of these
Answer
a ³ 12
Explanation
Solution
2(2a) = (51 + x + 51 – x) + (25x + 25–x)
̃ a = 5 (5x + 5–x) + (52x + 5–2x)
= 5 {(5x/2 – 5–x/2)2 + 2.5x/2 . 5–x/2} + {(5x – 5–x)2 + 2 . 5x . 5–x}
= 5 {(5x/2 – 5–x/2)2 + 2} + (5x – 5–x)2 + 2 a ³ 5 × 2 + 2 a ³ 12.