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Question: For what values of \(k,\) the system of equations will represent the coincident lines \(x+5y-7=0\) a...

For what values of k,k, the system of equations will represent the coincident lines x+5y7=0x+5y-7=0 and 4x+20y+k=0?4x+20y+k=0?
(a)28\left( a \right) 28
(b)28\left( b \right) -28
(c)26\left( c \right)-26
(d)\left( d \right) None of these

Explanation

Solution

We know that the lines which coincide or lie on top of each other are called the coincident lines. So, the equations of these lines are related. The equation of a line coincident with another is the multiple of the equation of the former.

Complete step-by-step answer:
Let us consider the given equations of lines, x+5y7=0x+5y-7=0 and 4x+20y+k=0.4x+20y+k=0.
We are asked to find the value of kk for which these two lines represent the coincident lines.
We know that the lines which coincide or lie on top of each other are called coincident lines.
So, a line ll is said to be coincident with another line m,m, if the both lie on top of each other in the plane. So, we can say that the equation of mm is a multiple of the equation of the line l.l. Or in other words, we can say that the equation of the line ll is a multiple of the equation of the line m.m.
Here, the equations are x+5y7=0x+5y-7=0 and 4x+20y+k=0.4x+20y+k=0.
So, we can say that if these two lines are coincident lines, then these two equations are multiples of each other.
Now, we can see the coefficient of xx in the first equation is 11 and that of the second equation is 44 which is a multiple of 1.1. And 4=4×1.4=4\times 1.
Similarly, the coefficient of yy in the first equation is 55 and that of the second equation is 2020 which is a multiple of 5.5. And 20=4×5.20=4\times 5.
Now, we can see that the constant term kk has to be a multiple of the constant term 7-7 in the first equation. And as all other coefficients of the second equations are multiples of 4,4, the constant terms will also be a multiple of 4.4. We can say that the constant term is a multiple of both 44 and 7.-7. Therefore, k=4×7=28.k=4\times -7=-28.
So, the second equation will become  4x+20y28=0.~4x+20y-28=0.
When we take 44 out, we will get 4(x+5y7)=4×0.4\left( x+5y-7 \right)=4\times 0.
Hence the given equations represent the coincident lines when k=28.k=-28.

Note: We know that the parallel lines never have common points because they never intersect with each other. But all the points of coincident lines are common for they lie on top of each other.