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Question

Mathematics Question on Trigonometry

For what value of θ\theta, sin2θ+sinθ+cos2θ\sin^2\theta + \sin\theta + \cos^2\theta is equal to 2?

A

4545^\circ

B

00^\circ

C

9090^\circ

D

3030^\circ

Answer

9090^\circ

Explanation

Solution

We know that:

sin2θ+cos2θ=1\sin^2 \theta + \cos^2 \theta = 1

The given expression is:

sin2θ+sinθ+cos2θ=1+sinθ\sin^2 \theta + \sin \theta + \cos^2 \theta = 1 + \sin \theta

For this to equal 2:

1+sinθ=2    sinθ=11 + \sin \theta = 2 \implies \sin \theta = 1

The value of θ\theta for which sinθ=1\sin \theta = 1 is 9090^\circ.