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Question: For what value of p the points (1, 1, p) and (–3,0,1) be equidistant from the plane \[\overrightar...

For what value of p the points (1, 1, p) and

(–3,0,1) be equidistant from the plane

r.(3i^+4j^12k^)+13=0\overrightarrow{r}.(3\widehat{i} + 4\widehat{j}–12\widehat{k}) + 13 = 0

A

1

B

73\frac{7}{3}

C

– 1

D

37\frac{3}{7}

Answer

73\frac{7}{3}

Explanation

Solution

Distance between the point & the plane is

Ž a.ndn\left| \frac{\overrightarrow{a}.\overrightarrow{n}–d}{\left| \overrightarrow{n} \right|} \right|