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Question: For what value of \( k \) , do the equations \( 3x - y + 8 = 0 \) and \( 6x - ky = - 16 \) represent...

For what value of kk , do the equations 3xy+8=03x - y + 8 = 0 and 6xky=166x - ky = - 16 represent coincident lines?
A.Solution of 3k9=0{3^k} - 9 = 0
B.Solution of 2k8=0{2^k} - 8 = 0
C. 22
D. 33

Explanation

Solution

Hint : As we can see that the above equations are linear equations in two variables. An equation for a straight line is called a linear equation. We know that the standard form of linear equations in two variables is Ax+By=CAx + By = C . With a pair of linear equations in two variables, the condition of coincident lines is a1a2=b1b2=c1c2\dfrac{{{a_1}}}{{{a_2}}} = \dfrac{{{b_1}}}{{{b_2}}} = \dfrac{{{c_1}}}{{{c_2}}} .

Complete step-by-step answer :
Here we have the equations 3xy+8=03x - y + 8 = 0 and 6xky=166x - ky = - 16 . We can write the second equation as 6xky+16=06x - ky + 16 = 0 .
Here we have a1=3,a2=6,b1=1,b2=k,c1=8,c2=16{a_1} = 3,{a_2} = 6,{b_1} = - 1,{b_2} = - k,{c_1} = 8,{c_2} = 16 .
So by putting these in the formula we can write 36=1k=816\dfrac{3}{6} = \dfrac{{ - 1}}{{ - k}} = \dfrac{8}{{16}} .
We can write 36\dfrac{3}{6} as 12\dfrac{1}{2} and also 816\dfrac{8}{{16}} can be written as 12\dfrac{1}{2} . So we can write the expression as 12=1k=12\dfrac{1}{2} = \dfrac{1}{k} = \dfrac{1}{2} .
Since we can see that two of the values are the same, we can equate any one to find the value of kk .
So we can write 12=1k\dfrac{1}{2} = \dfrac{1}{k} . By cross multiplication it gives us k=2k = 2 .
Now in the first option we have Solution of 3k9=0{3^k} - 9 = 0 . We can write it as 3k=9{3^k} = 9 .
WE know that 9=329 = {3^2} , so by putting this in the equation we can write 3k=32{3^k} = {3^2} .
So by comparing we have k=2k = 2 .
Hence the option (a) and (c) are correct.
So, the correct answer is “Option A and C”.

Note : We should know that coincident lines means that the line that lies upon each other. We have two pair of equations i.e. a1x+b1y+c1=0{a_1}x + {b_1}y + {c_1} = 0 and a2x+b2y+c2=0{a_2}x + {b_2}y + {c_2} = 0 , by comparing the given equations in questions with these we have calculated the value. We know that the slope intercept form of a linear equation is y=mx+cy = mx + c ,where mm is the slope of the line and bb in the equation is the y-intercept and xx and yy are the coordinates of x-axis and y-axis , respectively.