Question
Question: For what value of \( k \) , do the equations \( 3x - y + 8 = 0 \) and \( 6x - ky = - 16 \) represent...
For what value of k , do the equations 3x−y+8=0 and 6x−ky=−16 represent coincident lines?
A.Solution of 3k−9=0
B.Solution of 2k−8=0
C. 2
D. 3
Solution
Hint : As we can see that the above equations are linear equations in two variables. An equation for a straight line is called a linear equation. We know that the standard form of linear equations in two variables is Ax+By=C . With a pair of linear equations in two variables, the condition of coincident lines is a2a1=b2b1=c2c1 .
Complete step-by-step answer :
Here we have the equations 3x−y+8=0 and 6x−ky=−16 . We can write the second equation as 6x−ky+16=0 .
Here we have a1=3,a2=6,b1=−1,b2=−k,c1=8,c2=16 .
So by putting these in the formula we can write 63=−k−1=168 .
We can write 63 as 21 and also 168 can be written as 21 . So we can write the expression as 21=k1=21 .
Since we can see that two of the values are the same, we can equate any one to find the value of k .
So we can write 21=k1 . By cross multiplication it gives us k=2 .
Now in the first option we have Solution of 3k−9=0 . We can write it as 3k=9 .
WE know that 9=32 , so by putting this in the equation we can write 3k=32 .
So by comparing we have k=2 .
Hence the option (a) and (c) are correct.
So, the correct answer is “Option A and C”.
Note : We should know that coincident lines means that the line that lies upon each other. We have two pair of equations i.e. a1x+b1y+c1=0 and a2x+b2y+c2=0 , by comparing the given equations in questions with these we have calculated the value. We know that the slope intercept form of a linear equation is y=mx+c ,where m is the slope of the line and b in the equation is the y-intercept and x and y are the coordinates of x-axis and y-axis , respectively.