Question
Quantitative Aptitude Question on Number Systems
For two sets A and B, let AΔB denote the set of elements which belong to A or B but not both. If P = {1,2,3,4}, Q = {2,3,5,6,}, R = {1,3,7,8,9}, S = {2,4,9,10}, then the number of elements in (PΔQ)Δ(RΔS) is
A
9
B
7
C
6
D
8
Answer
7
Explanation
Solution
The correct answer is (B):
P = {1,2,3,4} and Q = {2,3,5,6,}
PΔQ = {1,4,5,6}
R = {1,3,7,8,9} and S = {2,4,9,10}
RΔS = {1,2,3,4,7,8,10}
(PΔQ)Δ(RΔS) = {2,3,5,6,7,8,10}
Thus, there are 7 elements in (PΔQ)Δ(RΔS)
hence, 7 is the correct answer.