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Question

Mathematics Question on Functions

For three positive integers p,q,r,xpq2=yyr=zp2rp , q , r , x^{p q^2}=y^{y r}=z^{p^2 r } and r=pq+1r = pq +1 such that 3,3logyx,3logzy3,3 \log _y x, 3 \log _z y 7logxz7 \log _x z are in AP with common difference 12\frac{1}{2} Then rpqr-p-q is equal to

A

6

B

2

C

12

D

6-6

Answer

2

Explanation

Solution

pq2=logx​λ
qr=logy​λ
p2r=logz​λ
logy​x=pq2qr​=pqr​…….(1)
logx​z=p2rpq2​=prq2​………(2)
logz​y=qrp2r​=qp2​………(3)
3,pq3r​,q3p2​,pr7q2​ in A.P
pq3r​−3=21​
r=67​pq………(4)
r=pq+1
pq=6………(5)
r=7…………(6)
q3p2​=4
After solving p=2 and q=3