Question

For the water gas reaction

C (s) + H₂O (g) $\rightleftarrows$ CO (g) + H₂ (g)

At 1000 K the standard Gibbs free energy change of the reaction is – 8.314 kJ/mol. Therefore at 1000 K the equilibrium constant of the above water gas reaction is-

• A. 1
• B. 10
• C. $\frac{1}{e}$
• D. 2.718

Answer 1

Answer: (D)

2.718

Answer 2

D_rG⁰ = – 8.314 × 10³

\ – D_rG⁰ = 8.314 × 10³ = RT ln K_eq

or 8.314 × 10³ = 8.314 × 10³ ln K_eq

or ln K_eq = 1 = ln e

or K_eq = e = 2.718