Solveeit Logo

Question

Question: For the values of \[{x_1},\;{x_2},{\text{ }} \ldots \ldots \ldots .{x_{101}}\] of a distribution \({...

For the values of x1,  x2, .x101{x_1},\;{x_2},{\text{ }} \ldots \ldots \ldots .{x_{101}} of a distribution x1<x2<x3.<x100<x101{x_1} < {x_2} < {x_3} \ldots \ldots . < {x_{100}} < {x_{101}}. The mean deviation of this distribution with respect to a number kk will be minimum when kk is equal to –
a) x1{x_1}
b) x51{x_{51}}
c) x50{x_{50}}
d) x1+x2+.......+x101101\dfrac{{{x_1} + {x_2} + ....... + {x_{101}}}}{{101}}

Explanation

Solution

In this question, they give one distribution. From that distribution we have to choose which term is equal to k when the mean deviation of this distribution with respect to k will be minimum. We solve this problem by taking k as the median of the given observation.

Complete step-by-step answer:
As we know mean deviation is minimum when median has been taken.
Therefore, here kk is taken as the median of the given observations.
Total number of observations in the question is 101101.
Now we have to apply the formula of median which is n+12\dfrac{{n + 1}}{2}
Since kk is the median and n=101n = 101 in this question therefore we can write-
k=n+12\Rightarrow k = \dfrac{{n + 1}}{2}
By substituting the total number of observations,
k=101+12\Rightarrow k = \dfrac{{101 + 1}}{2}
Adding the terms we get,
k=1022\Rightarrow k = \dfrac{{102}}{2}
Dividing the terms we get,
k=51\Rightarrow k = 51
Hence, k=51thk = 51^{th} observation
\therefore Thus, k=x51k = {x_{51}}

So, the correct answer is “Option b”.

Note: Mean, median and mode are the three kinds of averages which have wide application in statistics.
Median is generally used to find the middle value or centre of a set of data or information.
It can also be used for an open-end distribution and it is more useful than mean.
The main formula which is used for finding out the value of median for an odd discrete series is n+12\dfrac{{n + 1}}{2} where n represents the total number of data or numbers available in a distribution and the formula for even discrete series is 12[n2+(n2+1)]\dfrac{1}{2}[\dfrac{n}{2} + (\dfrac{n}{2} + 1)]
It is only applicable in quantitative data but not qualitative.
Value of the median is not dependent on all the values of the data in a data set and it does not depend on the individual value of a particular data of a set.