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Question: For the system \(3 A + 2 B\) ⇌<img src="https://cdn.pureessence.tech/canvas_203.png?top_left_x=1309&...

For the system 3A+2B3 A + 2 B, the expression for equilibrium constant is.

A

[3A][2B]C\frac { [ 3 A ] [ 2 B ] } { C }

B

[C][3A][2B]\frac { [ C ] } { [ 3 A ] [ 2 B ] }

C

[A]3[B]2[C]\frac { [ A ] ^ { 3 } [ B ] ^ { 2 } } { [ C ] }

D

[C][A]3[B]2\frac { [ C ] } { [ A ] ^ { 3 } [ B ] ^ { 2 } }

Answer

[C][A]3[B]2\frac { [ C ] } { [ A ] ^ { 3 } [ B ] ^ { 2 } }

Explanation

Solution

Equilibrium constant for the reaction ,

3A + 2B ⇌ C is. K =[C][A]3[ B]2= \frac { [ \mathrm { C } ] } { [ \mathrm { A } ] ^ { 3 } [ \mathrm {~B} ] ^ { 2 } }.