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Question

Physics Question on Energy in simple harmonic motion

For the system given below, find time period of oscillation?

A

103\frac{10}{\sqrt{3}}

B

10310\sqrt{3}

C

203\frac{20}{\sqrt{3}}

D

20320\sqrt{3}

Answer

203\frac{20}{\sqrt{3}}

Explanation

Solution

By energy method 12Kx2+12mv2+12lω2=C\frac{1}{2}Kx^{2}+\frac{1}{2}mv^{2}+\frac{1}{2}l\omega^{2}=C 12.K.2x.dxdt+12.m.2vdvdt+12I.+2vr2dvdt=0\frac{1}{2}.K.2x.\frac{dx}{dt}+\frac{1}{2}.m.2v \frac{dv}{dt}+\frac{1}{2}I.+\frac{2v}{r^{2}} \frac{dv}{dt}=0 Kxv+M4va+M2a.v=0Kxv +\frac{M}{4}va+\frac{M}{2}a.v=0 Kx=3Ma4-Kx=\frac{3Ma}{4} a=4K3M.x=ω2xa=-\frac{4K}{3M}.x=-\omega^{2}x ω2=4K3M\omega^{2}=\frac{4K}{3M} ω=4K3M=4×1003×1=203\omega=\sqrt{\frac{4K}{3M}}=\sqrt{\frac{4\times100}{3\times1}}=\frac{20}{\sqrt{3}} sec