Question
Physics Question on Energy in simple harmonic motion
For the system given below, find time period of oscillation?
A
310
B
103
C
320
D
203
Answer
320
Explanation
Solution
By energy method 21Kx2+21mv2+21lω2=C 21.K.2x.dtdx+21.m.2vdtdv+21I.+r22vdtdv=0 Kxv+4Mva+2Ma.v=0 −Kx=43Ma a=−3M4K.x=−ω2x ω2=3M4K ω=3M4K=3×14×100=320 sec