Question

For the square planar complex $[M(a)(b)(c)(d)]$ (where, $M =$ central metal and $a, b, c$ and $d$ are monodentate ligands), the number of possible geometrical isomers are

• A. 1
• B. 2
• C. 3
• D. 4

Answer 1

Answer: (C)

3

Answer 2

For $[M [a][b][c][d]]$ square planar complex, the number of possible geometrical isomers is three which is obtained by fixing the position of one of the ligands say $a$ while the other ligands $b, c$ and $d$ are placed trans to it.