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Chemistry Question on Equilibrium

For the reversible reaction A(s)+B(g)C(g)+D(g):ΔG0=350kJ.A_{(s)}+B_{(g)} \rightleftharpoons C_{(g)}+D_{(g)}: \Delta G^{0}=-350 kJ . Which one of the following statements is true?

A

Equilibrium constant is greater than one

B

The entropy change is negative.

C

The reaction is thermodynamically not feasible

D

The reaction should be instantaneous

Answer

Equilibrium constant is greater than one

Explanation

Solution

In the reversible reaction,

A(s)+B(g)C(g)+D(g);A(s)+B(g) \rightleftharpoons C(g)+D(g);
ΔG=350kJ\Delta G^{\circ}=-350\, k J

Since, the randomness increases (because solid is changing into gas), entropy will increase and thus, ΔS\Delta S is positive. Reversible reaction never undergo to completion (ie, never be instantaneous).

\because For the given reaction, ΔG=350kJ\Delta G^{\circ}=-350\, kJ and we know that

ΔG=RTlogK\Delta G^{\circ} =-R T \log K
350=RTlogK-350 =-R T \log K

ie, KK (equilibrium constant) is greater than one.

Moreover, the reaction is thermodynamically feasible.