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Question

Chemistry Question on Redox reactions

For the reduction of NO3NO^-_3 ion in an aqueous solution EE^\circ is +0.96V+ \,0.96\, V. Values of EE^\circ for some metal ions are given below V2+(aq)+2eV;E=1.19Vtt\, V^{2+}(aq)+2e^- \longrightarrow V;\, \, \, \, \, E^\circ = -1.19\, Vtt Fe3+(aq)+3eFe;E=0.04V\, Fe^{3+}(aq)+3e^- \longrightarrow Fe;\, \, \, \, \, E^\circ = -0.04 V Au3+(aq)+3eAu;E=+1.40V Au^{3+}(aq)+3e^- \longrightarrow Au;\, \, \, \, \, E^\circ = +1.40\, V Hg2+(aq)+2eHg;E=+0.86V Hg^{2+}(aq)+2e^- \longrightarrow Hg;\, \, \, \, \, E^\circ = +0.86 V The pair(s) of metals that is/are oxidised by NO3NO^-_3 in aqueous solution is (are)

A

VV and HgHg

B

HgHg and FeFe

C

FeFe and AuAu

D

FeFe and VV

Answer

FeFe and VV

Explanation

Solution

Metals with EE^\circ value less than 0.96 V will be able to reduce NO3NO^-_3
in aqueous solution.Therefore, metals V (EE^\circ = - 1.19 V),
Fe (EE^\circ = - 0.04 V), Hg (EE^\circ = 0.86 V) will all reduce NO3NO^-_3 but Au
(EE^\circ = 1.40 V) cannot reduce NO3NO^-_3 in aqueous solution.